4j-12x^2/3

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Solution for 4j-12x^2/3 equation: 


x in (-oo:+oo)

4*j-((12*x^2)/3) = 0

4*j-4*x^2 = 0

-4*x^2 = -(4*j) // : -4

x^2 = j

x^2 = j // ^ 1/2

abs(x) = j^(1/2)

x = j^(1/2) or x = -j^(1/2)

x in { j^(1/2), -j^(1/2) }

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